Pages

Nov 22, 2011

David Cronenberg Talks More Rob & Cosmopolis


I recently had the honor of speaking with director David Cronenberg, who was out promoting his new drama A Dangerous Method, which arrives in theaters November 23.

We also talked about his new thriller Cosmopolis, which hits theaters sometime next year and starsRobert Pattinson, Marion Cotillard, and Juliette Binoche. I asked him if Cosmopolis will be the movie that will separate Robert Pattinson from his Twilight past. Here's what the director had to say below.

"I have no control over that, obviously. All I know is, as with Keira, I thought that Robert was very underrated. I mean, Keira has done more work than Robert has, but in England, they're always on her for whatever weird English class reasons. I'm not sure what that is. I always thought she was a substantial actress, and I had no doubt that she could really ace this role. I felt the same about Rob. The fate of the movie, though, who knows. I certainly think this. I don't think that any director who's looking to see what Rob can do, will not be able to see how terrific he is by looking at Cosmopolis. Even if the movie isn't a success at the box office, creatively, as far as I'm concerned, it is a success, and for Rob, it totally is. He's brilliant in the movie, he's fabulous. If nothing else, it will be a great demo film for Rob, for any other director who's looking for a great actor."

The filmmaker also talked about shooting both Cosmopolis and A Dangerous Method back-to-back.

"It was a wonderful shoot, as was A Dangerous Method, actually. They were both very beautiful shoots, even though they were both quite different in tone, which, for me, is delightful, because, to do two movies, back-to-back, they are both so different. The one similarity is that they're both very dialogue-heavy. That was kind of interesting, but they have very different dialogue."

Source: MovieWeb | Via: RobstenDreams

No comments:

Post a Comment

Please comment respectfully and don't include any links or phone numbers.